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MediaCrawler 小红书爬虫源码分析 #11950

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guevara opened this issue Jan 16, 2025 · 0 comments
Open

MediaCrawler 小红书爬虫源码分析 #11950

guevara opened this issue Jan 16, 2025 · 0 comments

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@guevara
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guevara commented Jan 16, 2025

MediaCrawler 小红书爬虫源码分析



https://ift.tt/cqfPEhL






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def sign(a1="", b1="", x_s="", x_t=""):
"""
takes in a URI (uniform resource identifier), an optional data dictionary, and an optional ctime parameter. It returns a dictionary containing two keys: "x-s" and "x-t".
"""
common = {
"s0": 5,
"s1": "",
"x0": "1",
"x1": "3.3.0",
"x2": "Windows",
"x3": "xhs-pc-web",
"x4": "1.4.4",
"x5": a1,
"x6": x_t,
"x7": x_s,
"x8": b1,
"x9": mrc(x_t + x_s + b1),
"x10": 1,
}
encode_str = encodeUtf8(json.dumps(common, separators=(',', ':')))
x_s_common = b64Encode(encode_str)
x_b3_traceid = get_b3_trace_id()
return {
"x-s": x_s,
"x-t": x_t,
"x-s-common": x_s_common,
"x-b3-traceid": x_b3_traceid
}

def get_b3_trace_id():
re = "abcdef0123456789"
je = 16
e = ""
for t in range(16):
e += re[random.randint(0, je - 1)]
return e

def mrc(e):
ie = [
0, 1996959894, 3993919788, 2567524794, 124634137, 1886057615, 3915621685,
2657392035, 249268274, 2044508324, 3772115230, 2547177864, 162941995,
2125561021, 3887607047, 2428444049, 498536548, 1789927666, 4089016648,
2227061214, 450548861, 1843258603, 4107580753, 2211677639, 325883990,
1684777152, 4251122042, 2321926636, 335633487, 1661365465, 4195302755,
2366115317, 997073096, 1281953886, 3579855332, 2724688242, 1006888145,
1258607687, 3524101629, 2768942443, 901097722, 1119000684, 3686517206,
2898065728, 853044451, 1172266101, 3705015759, 2882616665, 651767980,
1373503546, 3369554304, 3218104598, 565507253, 1454621731, 3485111705,
3099436303, 671266974, 1594198024, 3322730930, 2970347812, 795835527,
1483230225, 3244367275, 3060149565, 1994146192, 31158534, 2563907772,
4023717930, 1907459465, 112637215, 2680153253, 3904427059, 2013776290,
251722036, 2517215374, 3775830040, 2137656763, 141376813, 2439277719,
3865271297, 1802195444, 476864866, 2238001368, 4066508878, 1812370925,
453092731, 2181625025, 4111451223, 1706088902, 314042704, 2344532202,
4240017532, 1658658271, 366619977, 2362670323, 4224994405, 1303535960,
984961486, 2747007092, 3569037538, 1256170817, 1037604311, 2765210733,
3554079995, 1131014506, 879679996, 2909243462, 3663771856, 1141124467,
855842277, 2852801631, 3708648649, 1342533948, 654459306, 3188396048,
3373015174, 1466479909, 544179635, 3110523913, 3462522015, 1591671054,
702138776, 2966460450, 3352799412, 1504918807, 783551873, 3082640443,
3233442989, 3988292384, 2596254646, 62317068, 1957810842, 3939845945,
2647816111, 81470997, 1943803523, 3814918930, 2489596804, 225274430,
2053790376, 3826175755, 2466906013, 167816743, 2097651377, 4027552580,
2265490386, 503444072, 1762050814, 4150417245, 2154129355, 426522225,
1852507879, 4275313526, 2312317920, 282753626, 1742555852, 4189708143,
2394877945, 397917763, 1622183637, 3604390888, 2714866558, 953729732,
1340076626, 3518719985, 2797360999, 1068828381, 1219638859, 3624741850,
2936675148, 906185462, 1090812512, 3747672003, 2825379669, 829329135,
1181335161, 3412177804, 3160834842, 628085408, 1382605366, 3423369109,
3138078467, 570562233, 1426400815, 3317316542, 2998733608, 733239954,
1555261956, 3268935591, 3050360625, 752459403, 1541320221, 2607071920,
3965973030, 1969922972, 40735498, 2617837225, 3943577151, 1913087877,
83908371, 2512341634, 3803740692, 2075208622, 213261112, 2463272603,
3855990285, 2094854071, 198958881, 2262029012, 4057260610, 1759359992,
534414190, 2176718541, 4139329115, 1873836001, 414664567, 2282248934,
4279200368, 1711684554, 285281116, 2405801727, 4167216745, 1634467795,
376229701, 2685067896, 3608007406, 1308918612, 956543938, 2808555105,
3495958263, 1231636301, 1047427035, 2932959818, 3654703836, 1088359270,
936918000, 2847714899, 3736837829, 1202900863, 817233897, 3183342108,
3401237130, 1404277552, 615818150, 3134207493, 3453421203, 1423857449,
601450431, 3009837614, 3294710456, 1567103746, 711928724, 3020668471,
3272380065, 1510334235, 755167117,
]
o = -1

def right_without_sign(num: int, bit: int=0) -> int:
val = ctypes.c_uint32(num).value >> bit
MAX32INT = 4294967295
return (val + (MAX32INT + 1)) % (2 * (MAX32INT + 1)) - MAX32INT - 1

for n in range(57):
o = ie[(o & 255) ^ ord(e[n])] ^ right_without_sign(o, 8)
rturn o ^ -1 ^ 3988292384






via 悖论の小黑屋

January 16, 2025 at 10:05AM
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