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I have the following use-case. Maybe I'm overlooking something but currently I don't see any way to do this without some extensive programming around dupd.
Say I have the following directory layout:
What I'm looking for is to remove all duplicate files from /path2/ keeping all files from /path1/ and one copy of every file unique to /path2/.
When I run dupd rmsh I'm not sure which copy is kept of every file, it can be either from /path1/ or /path2/.
When I run dupd dups -p /path2/ then the files foo and test are reported twice which makes it impossible to remove the dups report "blindly" because then I completely remove file foo from my system.
In above layout, it would work something like:
$ dupd scan ./files10/
done
$ dupd rmsh --path ./files10/path2/
# copy paste lines below in your terminal to remove the duplicates
rm ./files10/path2/hello
rm ./files10/path2/sub/foo
rm ./files10/path2/sub/test
rm ./files10/path2/test
Agreed the rmsh script isn't very flexible. I added it long ago but never used it myself so it hasn't received much attention.
Now that the 2.0 version is in development (so I have a chance to make incompatible changes from 1.x) it might be a good time to restructure how it works.
I have the following use-case. Maybe I'm overlooking something but currently I don't see any way to do this without some extensive programming around dupd.
Say I have the following directory layout:
What I'm looking for is to remove all duplicate files from
/path2/
keeping all files from/path1/
and one copy of every file unique to/path2/
.dupd rmsh
I'm not sure which copy is kept of every file, it can be either from/path1/
or/path2/
.dupd dups -p /path2/
then the filesfoo
andtest
are reported twice which makes it impossible to remove the dups report "blindly" because then I completely remove filefoo
from my system.In above layout, it would work something like:
Also attached files10 in zip.
files10.zip
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