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There is a section of code that cannot be viewed through printf, but it is possible through std::cout, how can this be done? |
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Answered by
nlohmann
Sep 23, 2023
Replies: 1 comment
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Answer selected by
Kolhun
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operator[]
returns a reference tobasic_json
which is nothingprint
can print. Tryarray["name"].get_ref<std::string&>.c_str()
.