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Merge pull request #1025 from mintheon/main
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[mintheon] Week10
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SamTheKorean authored Feb 16, 2025
2 parents e57e52c + a267055 commit 2d64456
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52 changes: 52 additions & 0 deletions invert-binary-tree/mintheon.java
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import java.util.ArrayDeque;
import java.util.Queue;

/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
//시간복잡도: O(n)
//공간복잡도: O(n)
class Solution {
public TreeNode invertTree(TreeNode root) {
if(root == null) {
return root;
}

Queue<TreeNode> queue = new ArrayDeque<>();
queue.add(root);

while(!queue.isEmpty()) {
TreeNode cur = queue.poll();

if(cur == null) {
continue;
}

TreeNode temp = cur.left;
cur.left = cur.right;
cur.right = temp;

if(cur.left != null) {
queue.add(cur.left);
}

if(cur.right != null) {
queue.add(cur.right);
}
}

return root;
}
}
41 changes: 41 additions & 0 deletions search-in-rotated-sorted-array/mintheon.java
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class Solution {
// 시간 복잡도: O(log n)
// 공간 복잡도: O(1);
public int search(int[] nums, int target) {
int left = 0;
int right = nums.length - 1;

while(left <= right) {
int mid = (left + right) / 2;

if(nums[mid] > nums[nums.length - 1]) {
left = mid + 1;
} else {
right = mid - 1;
}
}

int answer = binarySearch(nums, 0, left - 1, target);

return answer != -1 ? answer : binarySearch(nums, left, nums.length - 1, target);
}

private int binarySearch(int[] nums, int leftIndex, int rightIndex, int target) {
int left = leftIndex;
int right = rightIndex;

while(left <= right) {
int mid = (left + right) / 2;

if(nums[mid] == target) {
return mid;
} else if (nums[mid] < target) {
left = mid + 1;
} else {
right = mid - 1;
}
}

return -1;
}
}

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